Two small, equally charged spheres, each of mass m, are suspended from the same point by silk threads of length L . Initially, the spheres are separated by distance x << L . As the charge leaks out at the rate dq /dt , the spheres approach each other with relative velocity v = a/sqrt(x), where a is a constant. Find the rate at which charge leaks out. Show that dq/dt = 3/2asqrt(2pie0mg/L)Solution: |

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