Two tubes of gas are identical and are open only at one end. One tube contains neon (Ne) and the other krypton (Kr). Both are monatomic gases, have the same temperature, and may be assumed to be ideal gases. The fundamental frequency of the tube containing neon is 481 Hz.
Concepts:
(i) For a gas-filled tube open only at one end, the fundamental frequency (n = 1) is f1 = v/(4L), where v is the speed of sound and L is the length of the tube. How is the speed related to the properties of the gas?
(ii) All of the factors that affect the speed of sound in this problem are the same except for the atomic masses, which are given by 20.180 u for neon, and 83.80 u for krypton. Is the speed of sound in krypton greater than, smaller than, or equal to the speed of sound in neon? Why?
(iii) Is the fundamental frequency of the tube containing krypton greater than, less than, or equal to the fundamental frequency of the tube containing neon? Explain. Calculations: What is the fundamental frequency of the tube containing krypton?

1) You can buy this solution for 0,5$.
2) The solution will be in 8 hours.
3) If you want the solution will be free for all following visitors.
4) The link for payment paypal.me/0,5usd
5) After payment, please report the number of the task to the oneplus2014@gmail.com

New search. (Also 5349 free access solutions)

Use search in keywords. (words through a space in any order)