Statement of a problem № 11133


Suppose that the light falling on the polarizer in Figure 24.20 is partially polarized (average intensity = S̅P) and partially unpolarized (average intensity = S̅U). The total incident intensity is S̅P + S̅U, and the percentage polarization is 100 S̅P / (S̅P + S̅U). When the polarizer is rotated in such a situation, the intensity reaching the photocell varies between a minimum value of S̅min and a maximum value of S̅max. Show that the percentage polarization can be expressed as 100 (S̅max - S̅min)/(S̅max + S̅min). Figure 24.20

New search. (Also 5349 free access solutions)

To the list of lectures