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Statement of a problem № 3041

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Neon-23 beta-decays in the following way: 23Ne10->23Na11 + 0e(-1) + 0n0 where v is an antineutrino, a particle with no charge and no mass. Depending on circumstances, the energy carried away by the antineutrino can range from zero to the maximum energy available from the reaction. Find the minimum and maximum KE that the beta particle _le can have. Pertinent atomic masses are 22.994 5 u for 23Ne, and 22.989 8 u for 23Na. The mass of the beta particle is 0.000 55 u.

Solution:
Neon-23 beta-decays in the following way: 23Ne10->23Na11 + 0e(-1) + 0n0 where v

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