|
A uniform rod of mass m = 5.0 kg and length l = 90 cm rests on a smooth horizontal surface. One of the ends of the rod is struck with the impulse J = 3.0 N*s in a horizontal direction perpendicular to the rod. As a result, the rod obtains the momentum p = 3.0 N*s. Find the force with which one half of the rod will act on the other in the process of motion. |
| New search. (Also 5349 free access solutions) |