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Statement of a problem № 3704

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A soap bubble of radius R1 is given a charge q . Due to mutual repulsion of the surface charges the radius is increased to R2 , the pressure remaining constant. Show that the charge is given by q=[32/3pi^2e0pR1R2(R1^2+R1R2+R2^2)]^1/2

Solution:
A soap bubble of radius R1  is given a charge q . Due to mutual repulsion of the

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