(a) Show that the moment of inertia of a disc of radius R and mass M about an axis through the centre perpendicular to its plane is I = 1/2MR (b) A disc rolls without slipping along a horizontal surface with velocity u. The disc then encounters a smooth drop of height h, after which it continues to move with velocity v. At all times the disc remains in a vertical plane (Fig. 4.15). Show that v = sqrt(u^2+4gh/3)Solution: |

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